x^2-10x=63

Solution for x^2-10x=63 equation:

x^2-10x=63

We move all terms to the left:

x^2-10x-(63)=0

a = 1; b = -10; c = -63;
Δ = b2-4ac
Δ = -102-4·1·(-63)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{22}}{2*1}=\frac{10-4\sqrt{22}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{22}}{2*1}=\frac{10+4\sqrt{22}}{2}
$